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Sheila went to the store and bought 28 apples. She bought twice as many red apples as she bought green, and she bought one-fourth as many yellow as she did red. How many of each type of apple did she buy?
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this can be solved algebrically..
let she bought x yellow apples then she must have bought 4x red apples and 2x green apples hence we can write the equation as x+2x+4x=28
or 7x=28 x=4 yellow apples =4 red apples =16 green apples = 8
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