The scatter plot below shows the length of a spring (y ) for different forces applied on it (x):
Based on the scatter plot, what was the approximate kilogram force applied when the elongation was 12.3 cm? (4 points)
Select one:
a. 210
b. 236
c. 320
d. 326

Question

The scatter plot below shows the length of a spring (y ) for different forces applied on it (x):
 Based on the scatter plot, what was the approximate kilogram force applied when the elongation was 12.3 cm? (4 points)
Select one:
a. 210 
b. 236 
c. 320 
d. 326

anonymous · Answer

attachment

ranga · Answer

The scatter plot is more or less a straight line.
Try to fit a straight line of the form y = mx + b.
From the graph we can see the y-intercept is 0.5.  So b = 0.5
y = mx + 0.5   ---  (1)
Pick two points: (0,0.5) and (20,1.5)
Calculate the slope m.  m = (y2 - y1) / (x2 - x1) = ?
Substitute the m you find in equation (1)

Then set y = 12.3 and find x.