Question

parallel to the graph of 3x-5y=7 and passes through (0,-6). Write an equation in slope intercept form of the line satisfying the given conditions.

Answer 1

I'll give the steps to do this.
A. Find the slope.
If it is parallel to the other graph, then it must have the SAME slope. I'd change the equation to y=mx+b where m equals the slope and b equals the y intercept. So, whatever the coefficient is in this equation will be the slope.
B. Now, we need to make the new equation
y=mx+b
You've already found the slope (m) fill that in.
y=?x+b
b is the y intercept... Lucky you, your point IS the y intercept (-6). So that gaves you the b...
y equals the slope you found above * x + (-6)

Answer 2

so it is y=3x+6, right?

Answer 3

3x - 5y = 7
-5y = -3x + 7
y = 3/5x - 7/5

your slope is 3/5. A parallel line will have the same slope.
now we will use y = mx + b and solve for b
y = mx + b
slope(m) = 3/5
(0,-6) x = 0 and y = -6
now we sub
y = mx + b
-6 = 3/5(0) + b
-6 = b

therefore, your parallel line is : y = 3/5x - 6

Answer 4

Thank you for showing me the steps that help very much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 5

glad I could help :)

Answer 6

thank you again