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describe the position of a plane, 15 minutes after starting a race:

flight path equation: s(t)=0.1t(t-28)
velocity function: -0.2t+2.8

Question

WILL GIVE MEDALS FOR ANSWERING
describe the position of a plane, 15 minutes after starting a race:

flight path equation: s(t)=0.1t(t-28)
velocity function: -0.2t+2.8

ranga · Answer

Put t = 15 in s(t)=0.1t(t-28)  and  find s

anonymous · Answer

19.5KM How would I describe its position?

anonymous · Answer

first off, the velocity function cannot be that . Since velocity = ds/dt, it should be = 0.2t -2.8. Your sign is backward.
second, to describe the position, you write out the function of s under the form of parabola. It is S(t) = 0.1t^2 -2.8t . and solve for t = 15 minutes = 900second. (to me, I have to put everything on the basic unit) and sketch the function.|dw:1384650847448:dw|