Question

What is the equation in standard form of the line which passes through (4, –2) and has a slope of –3?

OPTIONS:
A)x + 3y = 10
B) x + 3y = –10
C) 3x + y = 10
D) 3x + y = –10

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&(4\quad ,&-2)
\end{array}
\\\quad \\

slope = m= -3
\\ \quad \\

y-y_1=m(x-x_1)\quad \textit{plug in your values and solve for "y"}\)

Answer 2

i dont get how to solve foy y

Answer 3

well, like you did on the previous one, you isolate "y"

Answer 4

hmmm actually the choices show that you don' t have to :/

Answer 5

y-(-2)=-3(x-4)
y+2=-3x+12
y=3x+10

Answer 6

y -(-2) = -3 ( x - 4)

y+2 = -3x+12

3x + y = 10

Answer 7

okay thanks

Answer 8

pretty much, yes, yours is correct, just missed the - in the last line

Answer 9

y-(-2)=-3(x-4)
y+2=-3x+12
y=3x+10

Answer 10

i dont get how to solve foy y