Question

solve the equation 13^(x-1)=2 ? I think logarithm is needed?

Answer 1

Yes, you will need logarithms. Can you solve from there?
\[\log_{13}2 = x-1 \]

Answer 2

\[\qquad b^{f(x)}=y\\
\log_b b^{f(x)}=\log_b y\\
\qquad f(x)=\log_b y\]

Answer 3

Thank you both for your help!!!!

Answer 4

@brendafn Did you find the answer?

Answer 5

I'm still trying to figure it out using what you gave me @pabloecortez07

Answer 6

@brendafn Since all you need to solve for is x, just add 1 to both sides :)

Answer 7

Oh okay!!! Thank you @pabloecortez07 :)

Answer 8

@brendafn No problem, glad to help.