Question

If x is a positive integer such that (x – 5)^2 = 4 and , what is the value of x?

Answer 1

(x-5)^2 = 4
square both sides.
x-5 = 2
add 5 to both sides.
x = 7

Answer 2

Done well.

@RichGrl20, do you understand why did he set it up as \[(x-5)^2 = 4\]
Are you 100% clear with this?

Answer 3

Oh, I am so stupid, sorry!

Answer 4

\[(x-5)^2 = 4\]
\[(x-5) = \pm 4\]

solve for x

Answer 5

\(\huge {\color{green} {Whatever,} }\) \(\huge {\color{green} {I'm} }\) \(\huge {\color{green} {out.} }\)

Answer 6

iits plus minus 2 sorry