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log(x) + log(8) = 1 Does x = 5/4 satisfy the equation? So after I plug it in for x, what do I do?
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\[Logx=1-Log8\] \[\huge {x ^{(1-Log8)}}=10\] \[\huge { x=\sqrt[(1-Log8)]{10}}\] The rest is on calculations.
\[Logx=1-Log8\] \[\huge {x ^{(1-Log8)}}=10\] \[\huge { x=\sqrt[(1-Log8)]{10}}\] The rest is on calculations.
My connection snapped.
My connection snapped.
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Snapped again, I'll be short.
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