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limit as x approaches negative infinity of the following function (cos(4x))/x
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without a calculator, how do I know the solution is 0?
can I break it up as 1/x and cos(4x)
when x approaches +infinity or -infinity what values can cos take ? yes, you can do that
it oscillates, I think
between ?
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0 because 0 is it midline (if my memory serves me)
it oscillates between -1 and +1 right ? it will take finite values in this interval only, its bounded, right ?
sorry, it has been a long time...
n, so lim x-> -infty 1/x = 0 and 0 times (ANY value between -1 to +1) is 0 only.
i meant, np, no problem :)
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Thanks :)
you're welcome ^_^
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