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OpenStudy (anonymous):
Factor given expression completely (2x-3)(3-x)(x-7)(3x+1)/(3x+2)(3-2x)(x-3)(7+x)
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OpenStudy (anonymous):
i have (x-7)(3x+1)/(3x+2)(7+x) is this correct?
OpenStudy (dumbcow):
its already factored...you just cancel like factors yes you are correct
OpenStudy (anonymous):
yes, okay thank you
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