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write the trigonometric expression as an algebraic expression. sin (arccos x + arcsin x)
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i got to (sin arccos x) x + (cos arcsin x) x
to find sin(arccos(x)), remember that sin^2+cos^2=1, so sin(arccos(x))=sqrt(1-cos(arrcos(x))^2). cos(arcsin(x)) can be found similarly.
thus sin(arccos(x))=cos(arcsin(x))=sqrt(1-x^2)
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