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Factor completely 169x^2 - 64. a. (13x + 8)(13x - 8) b. (13x + 8)^2 c. (13x - 8)^2 d. 13x - 8
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169x^2 - 64 (13x-8)(13+8) since there is no bx in this quadratic equation, you know that the values of the factor will be one negative and one positive, and since c is a negative number.
which one is it?
I just said it..
c?
(13x+8) (13x-8) I literally said it in my response ...
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