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3(a-5)=18
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To solve for a. Let's do an easy approach. \[\large \frac{ \cancel 3(a-5) }{ \cancel 3 } = \frac{ 18 }{ 3 }\] \[\large a - 5 = 18\] \[\large a = 23\]
Oh oops. I made a huge mistake
\[\large a - 5 = 6\] \[\large a = 11\] Sorry, my brain is still waking up >.<
another way is to distribute through the parenthesis 3(a - 5) = 18 3a - 15 = 18 3a = 18 + 15 3a = 33 (divide by 3) a = 11
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