Question

sin(pi/12)

Answer 1

\(\bf \cfrac{1}{12}\implies \cfrac{4}{12}-\cfrac{3}{12}\implies \cfrac{1}{12}\qquad thus\\ \quad \\
sin\left(\cfrac{\pi}{12}\right)\implies sin\left(\cfrac{4\pi}{12}-\cfrac{3\pi}{12}\right)\implies sin\left(\cfrac{\pi}{3}-\cfrac{\pi}{4}\right)\\ \quad \\ \quad \\
\textit{recall that }\quad sin(\alpha-\beta)=sin(\alpha)cos(\beta)-cos(\alpha)sin(\beta)\)