Y-1= - 3
— —
X+3 4
4(y-3)=-3(x+4)
= 4y-12 = -3x + 1
= 4y -12 + 3 = -3x +3 +1
= 4y -9 = 1
= 4y – 9 -1=1-1
=4y + 10
= 4y + 10
..4…….4
Y= 10 = 5
— —
4 2
Is this correct? This is Algebra II Ratios and proportions.

Question

Y-1= - 3
—         —
X+3      4
4(y-3)=-3(x+4)
= 4y-12 = -3x + 1
= 4y -12 + 3 = -3x +3 +1
= 4y -9 = 1
= 4y – 9 -1=1-1
=4y + 10
= 4y + 10
..4…….4
Y= 10 = 5
       —    —
        4     2
 Is this correct? This is Algebra II Ratios and proportions.

shamil98 · Answer

$$\large \frac{ y-1 }{ x+3 } = -\frac{ 3 }{ 4 }$$
is this your problem?..

shamil98 · Answer

Hello?..
Are you solving for x? for y? What are you supposed to do?

queenv · Answer

both and yes

queenv · Answer

solving for y

shamil98 · Answer

Okay.

shamil98 · Answer

Cross multiplying.
4(y-1) = -3(x+3)
distribute.
4y - 4 = -3x - 9
4y = -3x - 5
4y = -3x - 5 
y = (-3/4)x - 5/4

queenv · Answer

okay I am  not understanding the answer. How did you get the answer?

shamil98 · Answer

I divided everything by 4. to get y by itself.

queenv · Answer

I see, I did everything backwards.

queenv · Answer

Thanks

queenv · Answer

How do I give you a medal?

queenv · Answer

I did it