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Mathematics 15 Online
OpenStudy (anonymous):

How do you get this v = MT ∗ m^−1 ∗ 2^1/2 ∗ g^1/2 ∗ R^1/2cm ∗ (1 − cos θ)^1/2 from this v =MT/m sqrt 2gRcm (1 − cos θ)?

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