Question

Simplify the expression.
(2xy/y^-2)^-2

Answer 1

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Answer 2

That didn't lead to anywhere?

Answer 3

\[\left( \frac{ 2xy }{ y ^{-2} } \right)^{-2} \rightarrow \left( \frac{ 2xyy ^{2} }{ 1 } \right)^{-2} \rightarrow \left( 2xy^3 \right)^{-2}\rightarrow 2^{-2}x ^{-2}y ^{-6}\rightarrow \frac{ 1 }{ 4x ^{2}y ^{6} }\]

Answer 4

Does that make sense?

Answer 5

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