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Mathematics 16 Online
OpenStudy (anonymous):

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hartnn (hartnn):

factor the denominator

hartnn (hartnn):

\(a^2-b^2 = (a+b)(a-b)\)

hartnn (hartnn):

so, \(x-1 = (\sqrt{x})^2-1^2= ... ?\)

hartnn (hartnn):

also since we have to get the form of sin x/x also we can do this adjustment first, |dw:1384765915896:dw| got that adjustment ?

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