Question

Part A: Solve A = 9 over 2(x + 28) for x. (4 points)
Part B: Determine the value of x when A = 135. (2 points)
Part C: Solve –np – 40 > 10 for n. Show your work. (4 points)

Answer 1

Part A: A=\[\frac{ 9 }{ 2 }(x+28)\]

Answer 2

9/2(x+28) = A
multiply by the recprocal
2A/9 = x + 28
subtract 28
2A/9 - 28 = x

Answer 3

B. Just evaluate it, A=135
put that in and solve for x.
C. –np – 40 > 10
add 40
-np > 50
solving for n, divide by -p and flip the sign
n < 50/-p

Answer 4

for b?
(2*135)/9)-28=x
(270/9)-28=x
30-28=x
2=x

Answer 5

Yeah.

Answer 6

@Lena772 i have the same question right now