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Given Triangle ABC with a = 24, Angle A=101 degrees , and Angle B=36 degrees, find b. Round the sine value to the nearest thousandth and the answer to the nearest hundredth.
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can you draw a picture???
Do you know the law of sines?
When you have one side and the opposite angle given, you can use the law of sines. \( \dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C} \) In your case, use the first two fractions and use a = 36, A = 101 deg, B = 36 deg. Solve for b.
I don't know the law of sines, can you help me?
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I just did.
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