125 ^ 9x-2 = 150 can anyone help me figure out how to solve this step by step ?
is that \(1259x-2=150\) ? start by adding 2 on both sides...
but i don't think thats your question, you could've easily solved that
sorry , i mis wrote it , 9x - 2 is an exponent of 125
i think i have to use log but im not any good at logarithm /:
\(125 ^{9x-2} = 150\) taking log on both sides
use the property that \(\large \log a^b = b \log a \) on left side
9x-2 log ( 125 ) = log ( 150 ) is that right so far ?
@hartnn
yes it is but don't forget the brackets (9x-2) log 125 = log 150
i think now you can isolate the 'x'
but couldnt it also be log base 125 ^ 150 = 9x-2 ?
@hartnn
yes, it could be you have used change of base formula
\(9x-2 = \log_{125}150\) add 2 and then divide by 9
so log 150 / log 125 = 9x - 2 ?
i got .337 /.\ is that right ?
yeah i get that too weird answer :O
thank you soo muuch ! (:
welcome ^_^
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