Question

Find the area of the triangle with A = 60°, b = 11 feet, and c = 8 feet. Round to the nearest tenth.
A. 22 ft.^2
B. 38.1 ft.^2
C. 14.1 ft.^2
D. 12.4 ft.^2

Answer 1

Given the area of the triangle with A = 60°, b = 11 feet, and c = 8 feet.
a^2=b^2+c^2- 2bccosA // to find the value of a //
a^2 = 121 + 64 - 176 cos 60
a = √97
a = 9.8 feet
s = (a + b + c)/2
= (9.8 + 11 + 8)/2
= 14.4
A = √s(s - a)(s - b)(s – c) // area of triangle //
= √[14.4(14.4 - 9.8)(14.4 - 11)(14.4 - 8)]
A = 37.96
= 38 ft^2

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