Question

if if θ1,θ2,θ3,θ4 be 4 values of θ which satisfy equation 3tan3θ=tan(45+θ) then prove that
summation of tanθ1=0

Answer 1

@divu.mkr pls..hlp here

Answer 2

expand both tan 3x and tan (pi/4 + x)

Answer 3

3tanx-tan^3x/1-3tan^2x=1+tanx/1-tanx

Answer 4

then just cross multiply

Answer 5

tan ^3 might be zero...by that

Answer 6

yaa eqn is 8tanθ-6tan^2θ+3tan^4θ-1=0

Answer 7

prooved (:

Answer 8

tnx,,,,,i got it now