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Hello ( : could someone help me prove that the diagonals of the rhombus bisect the interior angles?
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So far I have : Triangle AED and CED are congruent triangles by the Side-Angle-Side theorem.
Triangles ABD and CBD are congruent by the SSS theorem and therefore angle ABD = angle CBD Hence the diagonal bisects angle B. Same logic for angles D, A and C.
How are they congruent by the SSS postulate?
In rhombus all sides are equal lengths. AB = CB ; AD = CD ; BD is shared by both triangles. Three sides of triangle ABD are identical to three sides of triangle CBD and therefore they are congruent.
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