Question

How will i find the integers given that the difference of their squares is 9. (I have problems in factoring :3 )

Answer 1

What is the original question?

Answer 2

The difference of the squares of two consecutive integers is 9.Find the integers.

Answer 3

Assume that the first number is x and the second number is x+1..so acrdng to the gvn conditions x^2-(x+1)^2=9.Nw solve this equation

Answer 4

\[x ^{2} - x ^{2} - 2x -1 = 9\] am i right?

Answer 5

then the x^2 will be cancelled?

Answer 6

Yes,now solve it further..you will get the value of x

Answer 7

i just got it. thanks :)

Answer 8

U r welcome :)