Question

Can someone please help? :)

Answer 1

2. -1

Answer 2

ok

Answer 3

\[\dfrac{9x}{x-x^2}\]
Simplify the following:
\[\dfrac{-9 x}{x-x^2}\]
Factor common terms out of \(x-x^2.\)
Factor -x out of \(x-x^2:\)
\[\dfrac{-9 x}{-x (x-1)}\]
Cancel common terms in the numerator and denominator of \(\frac{-9 x}{-x (x-1)}\).
\[\dfrac{-9 x}{-x (x-1)} = \dfrac{x}{x}\times \dfrac{-9}{-(x-1)} = \dfrac{-9}{-(x-1)}:\]
\[\dfrac{-9}{-(x-1)}\]
Simplify the sign of \(\dfrac{-9}{-(x-1)}\).
Multiply numerator and denominator of \(\dfrac{-9}{-(x-1)}\) by -1:
Answer:
\(\dfrac{9}{(x-1)}\)