Question

The equation of a line is y=-1/2x-2. What is the equation of the line that is perpendicular to the first line and passes through the point (2, –2)?
A.
y = 2x – 2
B.
y=1/2x - 3
C.
y = 2x – 6
D.
y = –2x + 2

Answer 1

y=mx+c

m=100(given)

y=100x+c

substitute 2000,3000
3000=200000+c
c=-197000

y=100x-197000


y=100x-197000

Answer 2

y = mx + b (solving for b)
3000 = 100(2000) + b
3000 = 200000 + b
3000 - 200000 = b
197,000 = b

so we have : y = 100x - 197,000

I agree with kc :)