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Chemistry 19 Online
OpenStudy (anonymous):

how many moles of MgS2O3 are in 201 g of the compound

OpenStudy (abb0t):

\(\sf \color{}{201~g~ MgS_2O_3 \times \frac{mol~ MgS_2O_3}{grams~of~MgS_2O_3}}\) you can find the grams by looking at your periodic table. The molar mass is on there.

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