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Solve for x: (4^x)+6(4^-x)=5 Medal for Answer
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is it \[ 4^x+6(4^{-x})=5\]
yes
hey u there?
So lets apply ln and see if we make sense \[ \ln (4^x)+ \ln (6*4^{-x})=\ln (5)\] \[x \ln (4) +ln(6)-x \ln (4) = \ln (5)\] Ya I am here. Just trying to see how to continue
Actually I gotta go home so I will be back in like 1/2 hr
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ok
makes sense now
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