algebra help
what do you need help with is there a specific question
i might be able to get help for you but i cant help you
okay that's fine I'm also waiting to see if @jigglypuff314 is available. He usually helps me when he can.
what values of m and n would make the denominator 0? If the denominator is 0, it would be undefined so that would be the restriction.
so you're saying it would be B?
hi, sorry it took me a while to get to this, the message system was glitching again. so, first, I'm a girl :P second, you can't divide by zero, therefore the denominator of a fraction cannot be zero so yes, B would be correct for 1 :)
it would be the same idea for 2 but you would have to factor the denominator first like solve for a^2 + 5a - 36 = 0 then the values you get for a would be the restrictions (or what a does not equal)
sorry about calling you a boy I never really looked at your picture and this whole time I thought your icon was a character from Naruto because I've only seen it when it was really tiny haha.
would it be D?
lol it's fine :P I just had to point it out because it was like the fifth time that happened ;)
idk im confused on that second one
close but not quite :) a^2 + 5a - 36 = 0 factors to (a + 9)(a - 4) = 0
so a = -9 and 4 right so it would be B do you see it now, or would you like for me to explain it further?
Maybe B then?
Oh yeah I see now. So you would just switch the signs right?
so for 3 you would simplify \[\frac{ 9b ^{2}-b+4-(2b ^{2}+b-8) }{ 3b - 2 }\] then simplify...and don't forget to distribute the negative :)
Option D?
not quite... try 9b^2 - b + 4 - 2b^2 - b + 8 =
oops woah D was way off I wasn't looking at it right. I think it's C.
D was closer than you think :P you just hadn't distributed the negative :) try again: 9b^2 - b + 4 - 2b^2 - b + 8 =
I mean B not C.
okay, then you were right :) good job!
now for 4, first get the denominators to be the same then add... so in the numerator: f - 6 + 11f(2f+3) =
D?
I think it'd either be D or B
because they both have 24.
hmm... neither D nor B .... f - 6 + 11f(2f+3) = f - 6 + 22f^2 + 33f =
Then it's either A or C. Sorry I'm in a rush I might have to come back later because I still have 4 more questions.
C would be correct :)
thans ill be back later, hopefully you're going to still be available by then
flip the part after the division, then cancel out a (x - 2) and a (6x)
I think its either A or D because they both have x^2
but the (5x^2 + 1) cannot cancel out the (5x^2 - 1) so D would be correct :)
oh yeah that's true
then for 6, the (x - 2), (x + 1), and (4) can cancel out
C or D?
D would be correct :)
crap I hate these >,< lol for 7 multiply top and bottom by 18 so (9 + 1) / (3 - 2) =
It would be 10 / 1 but 1 isn't really needed so it would be 10 which is D I'm guessing
D would be correct :D
for 8, multiply top and bottom by 3c so (8(3c) - 7(3)) / (4(3c) + 2) =
It would be A
yep :)
Yay! Thank you for another day of your help! :D You're basically my tutor haha
You're welcome ;) It's really nice working with you :)
You too :) Have a good rest of your day/night
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