Question

PLEASE HELP!!! will give medals!!!
1. which of the following is equal to square root (8x^9y^4
A. 3x^2y^2
B. 3x^4y^2 square root (2x
C. 9x^3y^2
D. 3x^3y^2 square root (2
2. what is the simplest form of the expression square root (2)- square root (10)/ square root (2)+square root (10)
A. -3/2+1/4 square root (10)
B. -3/2+1/2 square root (5)
C. 1-1/3 square root (5)
D. 1+1/2 square root (5)
3. what is the simplest form of the number 27^2/3
A. 3
B. 6
C. 9
D. 18

Answer 1

sqrt(8x^9y^4) = sqrt(8)*sqrt(x^9)*sqrt(y^4) = 2sqrt(2)*x^4*sqrt(x)*y^2 =
2x^4y^2 * sqrt(2x)

Answer 2

okay so wait whats the answer cause i got 3x^y^2 is that right ? for #1

Answer 3

are you sure that the question is
8x^9y^4
?

Answer 4

yes i am it says it on my work

Answer 5

because the answer is
2x^4y^2 * sqrt(2x)
which is none of the options

Answer 6

it must be 3x^4y^2

Answer 7

but look at the 3
if you square it you get 9
it is not compatible with the 8 that is given in the question.

Answer 8

well im just going to put 3x^4y^2 square root (2)
do yu know how to do 2 or 3 ? cause im really confused

Answer 9

this is the question ?
(sqrt(3) - sqrt(10)) /(sqrt(2) + sqrt(10))

Answer 10

I came here for my shiny medal

Answer 11

@Coolsector yes it is

Answer 12

first : 27^2/3
so it is like
(27^(1/3) )^2 = 3 ^ 2 = 9

Answer 13

where did you get 27 ?

Answer 14

(the third question)

Answer 15

oh okay i get it

Answer 16

now for the second:

(sqrt(2) - sqrt(10)) /(sqrt(2) + sqrt(10))

multiply and divide by sqrt(2) - sqrt(10)

you get:

(2 - 2sqrt(2)sqrt(10) + 10) / -8 =

-3/2 + (1/4)sqrt(2)sqrt(10) = -3/2 + (1/4) * 2 sqrt(5) = -3/2 + (1/2)sqrt(5)

Answer 17

oh okay now i get it thank you :)

Answer 18

yw :)

Answer 19

still problem with the first though.