Question

Would the range of f(x)=(x - 2)^2 + 2 be (x is greater than or equal to 0)?

Answer 1

no

Answer 2

since \((x-2)^2\geq 0\) for any \(x\), then \((x-2)^2+2\geq 2\)

Answer 3

Oh, so it would be x is greater than or equal to 2?
A) All real numbers
B) y ≥ 0
C) y < 2
D) y ≥ 2

Answer 4

@satellite73