Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

HELP!!!!!! What is the general form of the equation of the line shown? x + y - 2 = 0 x - y - 2 = 0 x + y + 2 = 0

OpenStudy (anonymous):

OpenStudy (jdoe0001):

same as before, pick 2 points, get the slope, and use the point-slope form, plug in your values and solve for "y"

OpenStudy (anonymous):

i dont have time tho that is y im on here asking

OpenStudy (jdoe0001):

http://www.youtube.com/watch?v=dBFbFMvEwQg

OpenStudy (anonymous):

@texaschic101 can you help please?

OpenStudy (texaschic101):

(-2,0) x1 = -2 and y1 = 0 (0,-2) x2 = 0 and y2 = -2 slope(m) = (y2 - y1) / (x2 - x1) m = (-2-0) / (0 - (-2) m = -2/2 = -1 y - y1 = m(x - x1) slope(m) = -1 (-2,0) x1 = -2 and y1 = 0 sub y - 0 = -1(x - (-2) y - 0 = -1(x + 2) y - 0 = -x - 2 y = -x - 2 x + y = -2 x + y + 2 = 0

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!