Question

sd

Answer 1

\(\bf \begin{array}{llll}
a&\bf b&\bf c\\
-2x^2&+x&+8=0
\end{array}\\ \quad \\ \text{quadratic formula}\\
x= \cfrac{ - b \pm \sqrt { b^2 -4ac}}{2a}\)

Answer 2

so those are your coefficients, thus \(\bf x= \cfrac{ - (1) \pm \sqrt { (1)^2 -4(-2)(8)}}{2(-2)}\)