7y + 4x = 3; (-4, -7) write the equation in slope intercept form of the line that is perpendicular to the graph of each equation and passes through the given point
we first need to find the slope of the equation. Do you know how to do that ?
nope
in y = mx + b form, the m position is the slope. 7y + 4x = 3 (put it in y = mx + b form) 7y = -4x + 3 y = -4/7x + 3/7 the slope is -4/7 you understand so far ?
yeah sorta..
now we are looking for a perpendicular line, so we need the negative reciprocal of that slope. All that means is we " flip " the slope and change the sign. So the negative reciprocal of -4/7 = 7/4 (you see how I flipped the slope and changed the sign) So we will be using slope(m) = 7/4 and (-4,-7) x = -4 and y = -7 y = mx + b now sub -7 = 7/4(-4) + b -7 = -28/4 + b -7 = - 7 + b -7 + 7 = b 0 = b so your equation is : y = 7/4x + 0
do you have any questions ?
omg i think so
It will take a little time to learn this, but once you get it down....and you will...it will be easy :)
you were such a big help. i actually get it. I'm solving one right now
good to hear. Keep practicing and you will learn all this in no time :)
thank you :)
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