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if I have a conical cup 24 inches across the top and 20 inches deep what is the height of the water when it fills half the volume of the cup?
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what is the volume of the full cup?
it might help to recall that the volume of a cone is 1/3 the volume of its representative cylindar
\[V=\frac13B_ah_o\] \[V/2=\frac16B_ah_o\] \[\frac13 B'h'=\frac16B_ah_o\] \[B'h'=\frac12B_ah_o\] \[h'=\frac1{2B'}B_ah_o\] hmm, might need to address the relationship between diameter and height to iron it out now
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