Question

m(2+n-m) + 3(3n+m^2-1)

Answer 1

@phi @ganeshie8

Answer 2

@Ballplop

Answer 3

(2m+nm-m^2)+(6n+3m^2-3)
2m+nm+2m^2-3
ANYBODY CHECK MY ANSWER TO SEE IF RIGHT!!!

Answer 4

@jim_thompson5910

Answer 5

If you want to distribute, then you'd get this


m(2+n-m) + 3(3n+m^2-1)


m*2+m*n-m*m + 3*3n + 3*m^2 - 3*1


2m + mn - m^2 + 9n + 3m^2 - 3

Answer 6

2m+mn+2m^2+9n-3 and then put it in exponential form

Answer 7

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\[\huge\text{Lana!!!}\]

Answer 8

\[\large\text{Danger zone!}\]