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hint: complete the square...
hint first step: \(y=x^2+14x+49+1\)
y=(x+7)^2+1
@MathStudent33 Could you tell me how you get the answer?
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@MathStudent33 don't just give out the answer pl0x
first coordinate of the vertex is always \(-\frac{b}{2a}\) which in your case it \(-\frac{14}{2}=-7\) so you know it will look like \[y=(x+7)^2+k\] \(k\) is the second coordinate of the vertex, which you can find by replacing \(x\) in \(y=x^2+14x+50\) by \(-7\) to find the \(y\) value
\[y\]\[=x^2+14x+50\]\(=x^2+7x+7x+49+1\) since 14=7+7 and 7^2=49\[=x(x+7)+7(x+7)+1\]\[=(x+7)(x+7)+1\]\[=(x+7)^2+1\] Learn more at: http://www.youtube.com/watch?v=7QMoNY6FzvM
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