Question

|6x-7|=5x+3

Answer 1

\[|6x-7|=5x+3\]\[(6x-7)^2=(5x+3)^2\]\[(6x-7)^2-(5x+3)^2=0\]\[(6x-7+5x+3)(6x-7-5x-3)=0\]\[(11x-4)(x-10)=10\]\(11x-4=0\) or \(x-10=0\)
\(x=\frac4{11}\)o r \(x=10\)

Answer 2

In the first step I squared both sides, then in the second step I put all things at the left hand side, and applied the difference of square identity in the third step.

Answer 3

hope that helps you in answering questions of the same kind :)

Answer 4

Thanks!

Answer 5

no problem :)