Question

The sum of three consecutive numbers is 48. What are the smallest of these numbers

Answer 1

so
first number =x
second = x + 1
and third = x + 2

x + x+1 + x+2 = 48

combine all your x values and combine all the constants and solve for 'x'

Answer 2

x+x+1+x+2=48. 3x+3=48. Subtract 3 and get 3x=45. Divide both sides by three and get 15.

Answer 3

Thanks