Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

how do i demonstrate that a polynomial identity works on numerical relationships?

OpenStudy (anonymous):

by the way, my identity is (x + a)^2 = x^2 + 2ax + a^2

OpenStudy (anonymous):

check with numbers

OpenStudy (anonymous):

sub any number in?

OpenStudy (anonymous):

should work for all real numbers, right? As it turns out, it works for complex numbers as well.

OpenStudy (anonymous):

oh cool thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!