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Factor: 27x^3-1 Please Show me a step by step way to this problem so that I can compare my work.
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okay one second.
\[27x^{3}-1\]=\[(3x^{3}-1^{3})\]=\[(3x-1) ((3x)^{2}+(3x-1)+(1)^{2})\]=\[(3x-1)(9x ^{2}+(-3x)+1)\]=\[(3x-1)(9x^{2}-3x+1)\]
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@agent0smith Can you hep me with this too? Please.
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