Question

Infinite limits!

Answer 1

again its all in the movie Mean Girls lol ☺☺☺

Answer 2

https://www.youtube.com/user/Hairfunfashion4teens

Answer 3

its simply 1

Answer 4

how is it 1? is it the last 2 terms becomes 0?

Answer 5

coz sin^2 x is bounded between -1 to 1 and denom is infinity so zero
and (real no.)/infi =0

Answer 6

does that apply too if sin^3x sin^4 and so on? sin will always be bounded between -1 to 1?

Answer 7

yes

Answer 8

bounded
-------- = 0
infinity

Answer 9

in limits contexxt

Answer 10

although there is a difference
\(0\leq \sin^2(x)\leq 1\) is whereas
\[-1\leq \sin(x)\leq 1\]

Answer 11

thanks! :D