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log base 5 (x+1) = 3 solve
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\[Log_ab=c--->a^c=b\]
\[alogb=\log(b^a)\]
If the base is not expressed, it is 10.
5 (x+1) = 3 5x+5=3 -5 -5 5x=-2 5x/5=-2/5 x=-2/5
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i think that right
Sammy that's wrong, it is logarithms.
okay sorry
\[Log_5(x+1)=3\]
I know the answer is 124 because i got it right but idk how to show the work to get the answer
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\[5^{3}=x+1\]\[125=x+1\]\[x=124\]YEP
Thank you i will have many more coming
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