Question

A parallelogram has the vertices (-1, 2), (4, 4), (2, -1) and (-3, -3). Determine what type of parallelogram. Find the perimeter and area; could anyone help me figure this out and how to do it? Please and thank you

Answer 1

to find distance between to points= (everything under square root) (second x-first x)^2 + (second y-first y)^2. you sub points in, so you will have 4 different answers for all 4 sides and then you add them up for the total perimeter.
to find which type of parallelogram it is, find the slopes between two different sets of points. if those two slopes are perpendicular (1/2 is perp. to -2 therefore reversed and added or taken away the negative) then it is a right angle.
If its a right angle and:
-all 4 sides are same length, it's a square
-there are 2 sides that are the same length and slope, and are perpendicular to the other 2 sides are different from the first set but also same length and slope for each other, it's a square,
If it's not perpendicular/right angle and:
-the sides are like a rectangle; two sets of 2 same side lengths; it's a parallelogram;
-there are 2 pairs of 2 sides touching, all same side lengths, it's a rhombus.

Answer 2

thank you for your help I think I understand it now!