Question

PLEASE HELPP !!

Answer 1

Wow that is pretty hard :/

Answer 2

Do you have a teacher to contact or ask?

Answer 3

Yes but I was told that I was "already taught" the information , when I wasn't ..

Answer 4

oh, i really hate when that happens...

Answer 5

I take notes on my school work, it really helps me out.

Answer 6

i can try to search it. would that help you out?

Answer 7

It might lol . And i do my schooling online btw

Answer 8

oh okay i do to... :)

Answer 9

Lol okayy .

Answer 10

if u solve the equation u have, by squaring
\[\large \sqrt{4x-6}=\sqrt{x} \]
\[\large 4x-6=x\]
\[\large 3x=6 \]
\[\large x=2 \]
right?

Answer 11

Correct !

Answer 12

now, if u replace x=2 into the original equation, does it actually solve the equation?

Answer 13

i.e., is it a valid solution?

Answer 14

Yes :o

Answer 15

so, is it extraneous or non-extraneous?

Answer 16

i.e., it is non-valid (extraneous) or valid (non-extraneous)?

http://en.wikipedia.org/wiki/Extraneous_and_missing_solutions

Answer 17

non-extraneous of course haha

Answer 18

I tried and tried........got no clue!!!!!!!!!!!!!!! :(

Answer 19

it's okay ! lol

Answer 20

Lol

Answer 21

u got it?

Answer 22

@helder_edwin , yess !

Answer 23

good. glad to help

Answer 24

i'm glad you did !