Question

which is equivalent to the following expression(2x^2+4xy-y^2)+(x^2+3xy-y^2)

3x^2-7xy-2y^2
3x^4+7xy-2y^4
3x^2+7xy-2y^2
2x^2-7xy+2y^2

Answer 1

(2x^2+4xy-y^2)+(x^2+3xy-y^2)
you just add same bases;
2x^2+x^2+4xy+3xy-y^2-y^2
=3x^2+7xy-2y^2
therefore the third one

Answer 2

thank you