Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

PLEASE HELP!! (sinxcosx)/tanx = ...

OpenStudy (anonymous):

\[tanx= sinx/cosx\]

OpenStudy (anonymous):

cos^2x

OpenStudy (anonymous):

its the same answer w/ my answer. thank you very much :)

OpenStudy (anonymous):

Anytime!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!