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OpenStudy (anonymous):
-9/16 + 5/8
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thomaster (thomaster):
\(\Large\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad}{bd}+\dfrac{bc}{bd}\) So \(\Large\dfrac{-9}{16}+\dfrac{5}{8}=\dfrac{-9*8}{16*8}+\dfrac{16*5}{16*8}=\dfrac{-72}{128}+\dfrac{80}{128}=\dfrac{-72+80}{128}\\\Large=\dfrac{8}{128}=\dfrac{1}{16}\)
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