Question

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Answer 1

test the given choices, lemme try the first one \(x^2\)

if x = 0, then y = \((0)^2\) so that checks out
if x = -1, then y = \((-1)^2\) well, that'd be 1, so that checks out too
if x = -2, then y = \((-2)^2\) well, that's not "2", so that one doesn't check out, thus is not that one

now test the other two choices